(x-8)(x^2+4x-12)=0

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Solution for (x-8)(x^2+4x-12)=0 equation:


Simplifying
(x + -8)(x2 + 4x + -12) = 0

Reorder the terms:
(-8 + x)(x2 + 4x + -12) = 0

Reorder the terms:
(-8 + x)(-12 + 4x + x2) = 0

Multiply (-8 + x) * (-12 + 4x + x2)
(-8(-12 + 4x + x2) + x(-12 + 4x + x2)) = 0
((-12 * -8 + 4x * -8 + x2 * -8) + x(-12 + 4x + x2)) = 0
((96 + -32x + -8x2) + x(-12 + 4x + x2)) = 0
(96 + -32x + -8x2 + (-12 * x + 4x * x + x2 * x)) = 0
(96 + -32x + -8x2 + (-12x + 4x2 + x3)) = 0

Reorder the terms:
(96 + -32x + -12x + -8x2 + 4x2 + x3) = 0

Combine like terms: -32x + -12x = -44x
(96 + -44x + -8x2 + 4x2 + x3) = 0

Combine like terms: -8x2 + 4x2 = -4x2
(96 + -44x + -4x2 + x3) = 0

Solving
96 + -44x + -4x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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